2626. Array Reduce Transformation
Tags
- Basic Array Transformations
Link
Question
Given an integer array
nums
, a reducer functionfn
, and an initial valueinit
, return the final result obtained by executing thefn
function on each element of the array, sequentially, passing in the return value from the calculation on the preceding element.This result is achieved through the following operations:
val = fn(init, nums[0]), val = fn(val, nums[1]), val = fn(val, nums[2]), ...
until every element in the array has been processed. The ultimate value ofval
is then returned.If the length of the array is 0, the function should return
init
.Please solve it without using the built-in
Array.reduce
method.
Example 1:
Input:
nums = [1,2,3,4]
fn = function sum(accum, curr) { return accum + curr; }
init = 0
Output: 10
Explanation:
initially, the value is init=0.
(0) + nums[0] = 1
(1) + nums[1] = 3
(3) + nums[2] = 6
(6) + nums[3] = 10
The final answer is 10.
Example 2:
Input:
nums = [1,2,3,4]
fn = function sum(accum, curr) { return accum + curr * curr; }
init = 100
Output: 130
Explanation:
initially, the value is init=100.
(100) + nums[0] * nums[0] = 101
(101) + nums[1] * nums[1] = 105
(105) + nums[2] * nums[2] = 114
(114) + nums[3] * nums[3] = 130
The final answer is 130.
Example 3:
Input:
nums = []
fn = function sum(accum, curr) { return 0; }
init = 25
Output: 25
Explanation: For empty arrays, the answer is always init.
Constraints:
0 <= nums.length <= 1000
0 <= nums[i] <= 1000
0 <= init <= 1000
Answer
JavaScript
/**
* @param {number[]} nums
* @param {Function} fn
* @param {number} init
* @return {number}
*/
var reduce = function (nums, fn, init) {
var res = init;
for (var i = 0; i < nums.length; i++) {
res = fn(res, nums[i]);
}
return res;
};