1431. Kids With the Greatest Number of Candies
Tags
- Array
Link
Question
There are
n
kids with candies. You are given an integer arraycandies
, where eachcandies[i]
represents the number of candies the $i^{th}$ kid has, and an integerextraCandies
, denoting the number of extra candies that you have.
Return a boolean arrayresult
of lengthn
, whereresult[i]
istrue
if, after giving the $i^{th}$ kid all theextraCandies
, they will have the greatest number of candies among all the kids, orfalse
otherwise.
Note that multiple kids can have the greatest number of candies.
Example 1:
Input: candies = [2,3,5,1,3], extraCandies = 3
Output: [true,true,true,false,true]
Explanation: If you give all extraCandies to:
- Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids.
- Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
- Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids.
- Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids.
- Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
Example 2:
Input: candies = [4,2,1,1,2], extraCandies = 1
Output: [true,false,false,false,false]
Explanation: There is only 1 extra candy.
Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy.
Example 3:
Input: candies = [12,1,12], extraCandies = 10
Output: [true,false,true]
Constraints:
n == candies.length
2 <= n <= 100
1 <= candies[i] <= 100
1 <= extraCandies <= 50
Answer
JavaScript
/**
* @param {number[]} candies
* @param {number} extraCandies
* @return {boolean[]}
*/
var kidsWithCandies = function (candies, extraCandies) {
const max = Math.max(...candies);
const res = [];
for (let i = 0; i < candies.length; i++) {
res.push(candies[i] + extraCandies >= max);
}
return res;
};
/**
* @param {number[]} candies
* @param {number} extraCandies
* @return {boolean[]}
*/
var kidsWithCandies = function (candies, extraCandies) {
const len = candies.length;
const max = Math.max(...candies);
return candies.map((candy) => candy + extraCandies >= max);
};